solve the quadratic.4x^2+4-20=0brainlist if you explain

Answer:x = -1/2(1 +√21) ≈ -2.79129x = -1/2(1 -√21) ≈ 1.79129Step-by-step explanation:We assume the middle term is supposed to be 4x.We can remove a common factor of 4 to simplify this a bit.   x^2 +x -5 = 0This is of the form   ax^2 +bx +c = 0where a=1, b=1, c=-5.__The quadratic formula gives the solutions as ...   [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]Filling in the given coefficients, we have ...   x = (-1 ±√(1^2 -4·1·(-5)))/(2·1)   x = (-1±√21)/2The solutions are x = -1/2(1 +√21) and -1/2(1 -√21)._____If what you wrote is what you intend, then the equation simplifies to 4x^2 -16 = 0.Dividing by 4 and factoring the difference of squares gives ...   x^2 -4 = 0   (x -2)(x +2) = 0These factors are zero (hence their product is 0) for the values x = 2 and x = -2.The solutions are x=2 and x=-2.